# What is the surface area of the solid created by revolving #f(x)=-2x^3-3x^2+6x-12# over #x in [2,3]# around the x-axis?

##### 1 Answer

Jan 20, 2016

Use the surface area of rotation integral:

Integrate the following:

#### Explanation:

may look bad it is not really. Take the derivative of f(x)

now integrate