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What is the sum of the arithmetic sequence 9, 14, 19, …, if there are 38 terms?

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1 Answer

Jan 14, 2016

#3857#

Explanation:

The sum of an arithmetic sequence where #x_n = a +(n-1)d#
is given by #sum_(n=0)^(n=38) = n/2(2a+(n-1)d)#

In this example #a=9# and #d=5# as the first term is#9# and the difference between each term is #5#. There are #38# terms

So #sum_(n=0)^(n=38) =38/2(2*9 + 37*5) =19(18+185)=19*203#

#=3857#

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