What is the standard form of $y = (x - 6) (- x + 4) (x - 3)$ $y= (x-6)(-x+4)(x-3)$ ?

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Answer 1 · 2018-05-29T01:33:40

$x^{3} + 13 x^{2} - 54 x + 72$ $color(crimson)(x^3 + 13x^2 - 54x + 72$ is the standard form.

$y = (x - 6) (4 - x) (x - 3)$ $y = (x-6) (4-x) (x - 3)$

$y = (4 x - 24 - x^{2} + 6 x) (x - 3)$ $y = (4x - 24 - x^2 + 6x)(x-3)$

$y = (- x^{2} + 10 x - 24) (x - 3) .$ $y = (-x^2 + 10x -24) (x-3).$

$y = - x^{3} + 10 x^{2} - 24 x + 3 x^{2} - 30 x + 72$ $y = -x^3 + 10x^2 - 24 x + 3x^2 - 30x + 72$

$x^{3} + 13 x^{2} - 54 x + 72$ $color(crimson)(x^3 + 13x^2 - 54x + 72$ is the standard form.

Degree of polynomial : 3

No. of terms : 4

What is the standard form of y=(x−6)(−x+4)(x−3) y= (x-6)(-x+4)(x-3)?