What is the standard form of $y= (x-6)(x-3)^2$ ?

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Answer 1 · 2018-05-28T14:50:56

$y = x^3 - 12x^2 + 45x - 54$ is the standard form.

$y = (x-6) * (x-3)^2$

$y = (x-6) * (x^2 -6x + 9)$

$y = x^3 -6x^2 + 9x - 6x^2 + 36x - 54$

$y = x^3 - 12x^2 + 45x - 54$ is the standard form.

What is the standard form of y= (x-6)(x-3)^2 y= (x-6)(x-3)^2 ?