What is the standard form of $y= (x-5)(x-2)(x-1)$ ?

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Answer 1 · 2017-12-18T00:04:39

$y = x^3-8x^2+17x-10$

Note that:

$(x-alpha)(x-beta)(x-gamma)$

$=x^3-(alpha+beta+gamma)x^2+(alphabeta+betagamma+gammaalpha)x-alphabetagamma$

So with $alpha=5$ , $beta=2$ and $gamma=1$ we find:

$(x-5)(x-2)(x-1) = x^3-8x^2+17x-10$

What is the standard form of y= (x-5)(x-2)(x-1) y= (x-5)(x-2)(x-1)?