What is the standard form of #y=(x - 3) (x - 2) #?

1 Answer
smendyka
Jan 17, 2017

See the entire solution process below:

Explanation:

To put this equation in standard form we need to multiply the two terms in parenthesis out. To multiply them out you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#y = (color(red)(x) - color(red)(3))(color(blue)(x) - color(blue)(2))# becomes:

#y = (color(red)(x) xx color(blue)(x)) - (color(red)(x) xx color(blue)(2)) - (color(red)(3) xx color(blue)(x)) + (color(red)(3) xx color(blue)(2))#

#y = x^2 - 2x - 3x + 6#

We can now combine like terms:

#y = x^2 + (-2 - 3)x + 6#

#y = x^2 - 5x + 6#

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