What is the standard form of y= (x+2)^2 -(x+3)^2 ?
1 Answer
Jun 23, 2018
y=-2x-5
Explanation:
Given -
y=(x+2)^2-(x+3)^2
y=(x^2+4x+4)-(x^2+6x+9)
y=x^2+4x+4-x^2-6x-9
y=-2x-5
y=-2x-5
Given -
y=(x+2)^2-(x+3)^2
y=(x^2+4x+4)-(x^2+6x+9)
y=x^2+4x+4-x^2-6x-9
y=-2x-5