What is the standard form of y= (x^2-1)(3x-1) + (x+1)^2?

1 Answer
Nov 20, 2015

y=3x^3-x+2

Explanation:

Given (color(blue)(x^2-1))(3x-1) + (color(red)(x+1))(x+1)

y= color(blue)(x^2)(3x-1) color(blue)(-1)(3x-1)color(red)(+x)(x+1)color(red)(+1)(x+1)

y=(3x^3-x^2)+(-3x+1)+(x^2+x)+(x+1)

Collecting like terms

y= 3x^3 +(-x^2+x^2)+(-3x+x+x)+(1+1)

y=3x^2+0-x+2

y=3x^3-x+2