What is the standard form of $y = 8 (x^{2} - 16) (x^{2} - 16) (x^{3} + 8)$ $y=8(x^2 - 16) (x^2 -16)(x^3 + 8)$ ?

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Answer 1 · 2018-05-31T05:54:34

$y = 8 x^{7} - 256 x^{5} + 64 x^{4} + 2048 x^{3} - 2048 x^{2} + 16394$ $color(crimson)(y = 8x^7 - 256x^5 + 64x^4 + 2048x^3 - 2048x^2 + 16394$

$y = 8 (x^{2} - 16) (x^{2} - 16) (x^{3} + 8)$ $y = 8(x^2 - 16) (x^2-16)(x^3+8)$

$y = 8 (x^{4} - 32 x^{2} + 256) (x^{3} + 8)$ $y = 8 (x^4 - 32x^2 + 256)(x^3+8)$

$y = 8 (x^{7} - 32 x^{5} + 256 x^{3} + 8 x^{4} - 256 x^{2} + 2048)$ $y = 8 (x^7 - 32x^5 + 256x^3 + 8x^4 - 256x^2 + 2048)$

$y = 8 x^{7} - 256 x^{5} + 64 x^{4} + 2048 x^{3} - 2048 x^{2} + 16394$ $color(crimson)(y = 8x^7 - 256x^5 + 64x^4 + 2048x^3 - 2048x^2 + 16394$

What is the standard form of y=8(x2−16)(x2−16)(x3+8)y=8(x^2 - 16) (x^2 -16)(x^3 + 8) ?