What is the standard form of $y=5(x-3)^2+3$ ?

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Answer 1 · 2015-11-17T12:16:57

Standard form $-> ax^2+bx+c$
If you meant to ask: 'What is this equation when presented in standard form'? Then you have $-> y=5x^2-6x+12$

The standard form is $y=ax^2+bx+c$

However, if you wish to present this equation in standard form we have:

$y= 5(x^2-6x+9) +3$
$y=5x^2-6x+12$

Answer 2 · 2015-11-17T12:35:49

$5x^2−30x+48$

$5(x−3)(x-3)+3$

$5(x-3$
$= (5 * x)+(5*$ - $3)$
$= 5x-15$

So now you have $5x−15(x-3)+3$ .

$5x−15(x-3)$
$= (5x*x)+(5x*$ - $3)+($ - $15*x)+($ - $15*$ - $3)$
$=5x^2-15x-15x+45$
$=5x^2-30x+45$

So now you have $5x^2-30x+45+3$ .

$45+3 = 48$

$5x^2-30x+48$

What is the standard form of y=5(x-3)^2+3y=5(x-3)^2+3?