What is the standard form of #y= 4(x-5)^3 + 1 #?

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Answer 1 · 2017-03-06T01:48:54

#4x^3-y-61=0#

Standard form is #Ax+By+C=0#

Using PEMDAS,

#y=4(x^3-15)+1#

#y=4x^3-60+1#

#y=4x^3-61#

#y-y=4x^3-61-y#

#4x^3-y-61=0#