What is the standard form of y=(3x-5)(2x+11)?

1 Answer
random12312312
Dec 12, 2015

y=6x^2+23x-55

Explanation:

Standard form is y=ax^2+bx+c

So you want to multiply the two factors together.
You can use Foil where you multiply the first two terms then the outer, inner, and last terms. Then add them together

3x*2x=6x

3x*11=33x

-5*2x=-10x

-5*11=-55

y=6x^2+33x+(-10x)+(-55)

Combine like terms

y=6x^2+23x-55

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