What is the standard form of y=3x^2(x-3) ?

1 Answer
Feb 12, 2017

y = 3x^3 - 9x^2

Or

y = 3x^3 - 9x^2 + 0x + 0

Explanation:

To put this in standard form expand the term in parenthesis on the right side of the equation:

y = 3x^2(x - 3) becomes:

y = (3x^2 xx x) - (3x^2 xx 3)

y = 3x^3 - 9x^2

Or

y = 3x^3 - 9x^2 + 0x + 0