What is the standard form of #y= (3x^2-x+2)^2-x #? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Taner Müftüoğlu Sep 25, 2016 just square the expression... Explanation: #y=(3x^2-x+2)^2 -x# #y= (3x^2-x+2)(3x^2-x+2)-x# #y=3x^2(3x^2-x+2) - x(3x^2-x+2) + 2(3x^2-x+2)-x# #y=9x^4-3x^3+6x^2 - 3x^3 +x^2 -2x +6x^2-2x+4-x# #y=9x^4-6x^3 + 13x^2-5x+4# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1651 views around the world You can reuse this answer Creative Commons License