What is the standard form of $y = (3 - x) (5 x^{2} - 2 x)$ $y=(3-x)(5x^2-2x)$ ?

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What is the standard form of $y = (3 - x) (5 x^{2} - 2 x)$ $y=(3-x)(5x^2-2x)$ ?

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Answer 1 · 2016-01-01T04:40:08

$y = - 5 x^{3} + 17 x^{2} - 6 x$ $y = -5x^3 +17x^2 -6x$

Explanation:

We just have to multiply the numbers inside the parenthesis. First, the first number in the first parenthesis multiplied by each number in the second one:
$3 \cdot 5 x^{2} + 3 \cdot (- 2 x) = 15 x^{2} - 6 x$ $3 * 5x^2 + 3 * (-2x) = 15x^2 - 6x$

And now, the same thing: the second number in the first parenthesis multiplied by each number in the second one:
$(- x) \cdot 5 x^{2} + (- x) \cdot (- 2 x) = - 5 x^{3} + 2 x^{2}$ $(-x) * 5x^2 + (-x) * (-2x) = -5x^3 + 2x^2$

Then, we just put them together and order them in the cubic function standard form( $y = A x^{3} + B x^{2} + C x + D$ $y = Ax^3 + Bx^2 +Cx +D$ ):
$y = 15 x^{2} - 6 x + - 5 x^{3} + 2 x^{2}$ $y = 15x^2 - 6x + -5x^3 + 2x^2$
$y = - 5 x^{3} + 17 x^{2} - 6 x$ $y = -5x^3 +17x^2 -6x$

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What is the standard form of $y = (3 - x) (5 x^{2} - 2 x)$ $y=(3-x)(5x^2-2x)$ ?

1 Answer

Explanation:

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What is the standard form of y=(3-x)(5x^2-2x)y=(3−x)(5x2−2x)y=(3-x)(5x^2-2x)?

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What is the standard form of $y = (3 - x) (5 x^{2} - 2 x)$ $y=(3-x)(5x^2-2x)$ ?