# What is the standard form of #y= (3/5x^2-1/2)(1/6x+7/8) #?

##### 1 Answer

Jan 3, 2016

#### Explanation:

Distribute using the FOIL method.

#y=overbrace(3/5x^2(1/6x))^("first")+overbrace(3/5x^2(7/8))^("outside")+overbrace(-1/2(1/6x))^("inside")+overbrace(-1/2(7/8))^("last")#

Multiply the fractions.

#y=1/10x^3+21/40x^2-1/12x-7/16#

This is in standard form since the degree of the each term is lower than the previous .