What is the standard form of $y = {(2 x - 9)}^{3} + {(6 x - 2)}^{2}$ $y= (2x-9)^3+(6x-2)^2$ ?

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Answer 1 · 2017-01-20T09:11:27

$y = 8 x^{3} - 72 x^{2} + 462 x - 725$ $y=8x^3-72x^2+462x-725$

$y = {(2 x - 9)}^{3} + {(6 x - 2)}^{2}$ $y=(2x-9)^3+(6x-2)^2$

$y = (2 x - 9) (2 x - 9) (2 x - 9) + (6 x - 2) (6 x - 2)$ $y=(2x-9)(2x-9)(2x-9)+(6x-2)(6x-2)$

$y = (8 x^{3} - 108 x^{2} + 486 x - 729) + (36 x^{2} - 24 x + 4)$ $y=(8x^3-108x^2+486x-729)+(36x^2-24x+4)$

$y = 8 x^{3} - 72 x^{2} + 462 x - 725$ $y=8x^3-72x^2+462x-725$

What is the standard form of y=(2x−9)3+(6x−2)2 y= (2x-9)^3+(6x-2)^2?