What is the standard form of #y= (-2x-5)(-x-4) #?

1 Answer
Shwetank Mauria
Feb 9, 2016

Standard form is #y = a*x^2+b*x+c#

Explanation:

It is clearly observable that when right hand side is expanded, highest degree of #x# is #a*x^2+b*x+c#

In fact this becomes #-2x*(-x-4)-5*(-x-4)#

i.e. #2x^2+8x+5x+20#

i.e. #2x^2+13x+20#

From this it is obvious that the standard form is #y=a*x^2+b*x+c#

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