What is the standard form of #y= (2x-3)(4x-4)^2 #? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Mark D. May 14, 2018 #y=32x^3-112x^2+128x-48# Explanation: #y=(2x-3)(4x-4)(4x-4)# #y=(8x^2-8x-12x+12)(4x-4)# #y=(8x^2-20x+12)(4x-4)# #y=32x^3-80x^2+48x-32x^2+80x-48# #y=32x^3-112x^2+128x-48# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1272 views around the world You can reuse this answer Creative Commons License