What is the standard form of $y=(2x + 3)(3x-6)$ ?

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Answer 1 · 2018-03-11T08:53:33

$y=6x^2-3x-18$

Standard form = Exponents in descending order.

First, expand the brackets using FOIL. See: How do you FOIL $(7-a)^2$ ? for more info.

$y=(2x*3x)+(2x*-6)+(3*3x)+(3*-6)$
$y=6x^2-12x+9x-18$
$y=6x^2-3x-18$

That is already in standard form/descending order.

What is the standard form of y=(2x + 3)(3x-6) y=(2x + 3)(3x-6) ?