What is the standard form of $y = (2 x - 2) (x + 7) (3 x - 14)$ $y= (2x-2)(x+7)(3x-14)$ ?

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Answer 1 · 2017-06-29T16:37:05

$y = 6 x^{3} + 8 x^{2} - 210 x - 196$ $y=6x^3+8x^2-210x-196$

$y = (2 x - 2) (x + 7) (3 x - 14)$ $y=(2x-2)(x+7)(3x-14)$

$y = {2 x (x + 7) - 2 (x + 7)} (3 x - 14)$ $y={2x(x+7)-2(x+7)}(3x-14)$

$y = (2 x^{2} + 14 x - 2 x - 14) (3 x - 14)$ $y=(2x^2+14x-2x-14)(3x-14)$

$y = (2 x^{2} + 12 x - 14) (3 x - 14)$ $y=(2x^2+12x-14)(3x-14)$

$y = 3 x (2 x^{2} + 12 x - 14) - 14 (2 x^{2} + 12 x - 14)$ $y=3x(2x^2+12x-14)-14(2x^2+12x-14)$

$y = 6 x^{3} + 36 x^{2} - 42 x - 28 x^{2} - 168 x - 196$ $y=6x^3+36x^2-42x-28x^2-168x-196$

$y = 6 x^{3} + 8 x^{2} - 210 x - 196$ $y=6x^3+8x^2-210x-196$

Hope u understood! :) ShantanuDash

What is the standard form of y= (2x-2)(x+7)(3x-14)y=(2x−2)(x+7)(3x−14) y= (2x-2)(x+7)(3x-14)?