What is the standard form of $y = (2 x - 2) (2 x + 2) (- x + 8)$ $y= (2x-2)(2x+2)(-x+8)$ ?

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Answer 1 · 2016-02-15T12:19:09

$y$ $y$ = $- 4 x^{3} + 32 x^{2} + 4 x - 32$ $-4x^3+32x^2+4x-32$

Standard form of equation $y = (2 x - 2) (2 x + 2) (- x + 8)$ $y=(2x−2)(2x+2)(−x+8)$ can be got by multiplying them and combining like terms.

$y = (2 x - 2) (2 x + 2) (- x + 8)$ $y=(2x−2)(2x+2)(−x+8)$

= $({(2 x)}^{2} - 2^{2}) (- x + 8)$ $((2x)^2-2^2)(-x+8)$

= $(4 x^{2} - 4) (- x + 8)$ $(4x^2-4)(-x+8)$ ie

$y$ $y$ = $- 4 x^{3} + 32 x^{2} + 4 x - 32$ $-4x^3+32x^2+4x-32$

What is the standard form of y= (2x-2)(2x+2)(-x+8)y=(2x−2)(2x+2)(−x+8) y= (2x-2)(2x+2)(-x+8)?