What is the standard form of y= (-2x^2-2)(4x-1) ?
1 Answer
Jan 21, 2016
- 8x^3 + 2x^2 - 8x + 2
Explanation:
Multiply out brackets (distributive law ) and collect ' like terms'.
-2x^2 (4x - 1 ) - 2 (4x - 1 ) = -8x^3 + 2x^2 - 8x + 2
= - 8x^3 + 2x^2 - 8x + 2
