What is the standard form of the equation of the parabola with a directrix at x=-6 and a focus at (12,-5)?

1 Answer
Sep 10, 2017

y^2+10y-36x+133=0

Explanation:

"for any point "(x,y)" on the parabola"

"the distance from "(x,y)" to the focus and directrix"
"are equal"

"using the "color(blue)"distance formula"

sqrt((x-12)^2+(y+5)^2)=|x+6|

color(blue)"squaring both sides"

(x-12)^2+(y+5)^2=(x+6)^2

rArrcancel(x^2)-24x+144+y^2+10y+25=cancel(x^2)+12x+36

rArry^2+10y-36x+133=0