What is the standard form of f(x)=(x+1)(x+3)+(-2x-1)^2 ?

1 Answer
Diane Martraire
Feb 27, 2016

The standard form of this equation is :
f(x) = 5x^2 + 8x + 4

Explanation:

The standard form of an equation should look like :
f(x) = ax^2 + bx + c

First, you have to develop the right member : (x+1)(x+3)+(-2x-1)^2

[ (x*x)+(x*3)+(1*x)+(1*3)] + [ (-2x)^2 - 2*(-2x*1) + 1^2]
Then, we can simplified it :
[ x^2+3x+x+3] + [ 4x^2 + 4x + 1]
x^2+4x+3 + 4x^2 + 4x + 1
5x^2+8x+4

So, f(x) = 5x^2 + 8x + 4

Related questions
See all questions in Polynomials in Standard Form
Impact of this question
2622 views around the world
You can reuse this answer
Creative Commons License