What is the standard form of a polynomial #(2x – 6)^2#?

1 Answer
smendyka
May 28, 2018

See a solution process below:

Explanation:

We can use this special rule for quadratics to put this expression in standard form.

#(color(red)(x) - color(blue)(y))^2 = (color(red)(x) - color(blue)(y))(color(red)(x) - color(blue)(y)) = color(red)(x)^2 - 2color(red)(x)color(blue)(y) + color(blue)(y)^2#

Substituting the values from the problem gives:

#(color(red)(2x) - color(blue)(6))^2 => (color(red)(2x) - color(blue)(6))(color(red)(2x) - color(blue)(6)) => (color(red)(2x))^2 - (2 * color(red)(2x) * color(blue)(6)) + color(blue)(6)^2 =>#

#4x^2 - 24x + 36#

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