What is the square root of 8 divided by square root of 5 minus square root of 2?

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Answer 1 · 2018-03-23T18:53:56

$\frac{2 \sqrt{10} + 4}{3}$ $(2sqrt10+4)/3$

$\frac{\sqrt{8}}{\sqrt{5} - \sqrt{2}}$ $sqrt8/(sqrt 5-sqrt 2)$

$:.(sqrt 5+sqrt 2)/(sqrt 5+sqrt 2)=1$

$:.=sqrt8/(sqrt 5-sqrt 2)xx (sqrt 5+sqrt 2)/(sqrt 5+sqrt 2)$

$(sqrt8(sqrt5+sqrt2))/((sqrt5-sqrt2)(sqrt5+sqrt2))$

$:.=(sqrt 8(sqrt 5+sqrt 2))/3$

$:.=(sqrt 8 sqrt 5+sqrt 8 sqrt 2)/3$

$:.=(sqrt(8*5)+sqrt(8*2))/3$

$:.=(sqrt 40+sqrt 16)/3$

$:.=(sqrt(2*2*2*5)+sqrt 16)/3$

$:.=sqrt2*sqrt2=2$

$:.=(sqrt(2*2*2*5)+4)/3$

$:.=(2 sqrt (2*5)+4)/3$

$:.=(2 sqrt10+4)/3$