What is the square root of $\frac{8}{18}$ $8/18$ ?

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Answer 1 · 2018-04-04T03:01:52

$\frac{2}{3}$ $2/3$

We want $\sqrt{\frac{8}{18}}$ $sqrt(8/18)$

Recalling that $\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}},$ $sqrt(a/b)=sqrta/sqrtb,$ we get

$\frac{\sqrt{8}}{\sqrt{18}}$ $sqrt8/sqrt18$

We need to simplify these roots.

$\sqrt{8} = \sqrt{4 \cdot 2} = \sqrt{4} \sqrt{2} = 2 \sqrt{2}$ $sqrt8=sqrt(4*2)=sqrt4sqrt2=2sqrt2$

$\sqrt{18} = \sqrt{9 \cdot 2} = \sqrt{9} \sqrt{2} = 3 \sqrt{2}$ $sqrt(18)=sqrt(9*2)=sqrt9sqrt2=3sqrt2$

So, we then have

$(2cancelsqrt2)/(3cancelsqrt2)=2/3$

What is the square root of 8/188188/18?