What is the square root of 15 times the square root of 6?

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Answer 1 · 2018-04-11T00:24:39

$3sqrt10$

Remember that $sqrta*sqrtb=sqrt(a*b)$

$sqrt15*sqrt6=sqrt(15*6)$

$sqrt90 rarr$ This can be simplified further

$sqrt(9*10) rarr$ 9 is a perfect square and can be taken out of the radical

$3sqrt10$

Answer 2 · 2018-04-11T00:28:15

$sqrt15sqrt6=color(blue)(3sqrt10$

$sqrt15sqrt6$

Apply rule: $sqrtasqrtb=sqrt(ab)$

$sqrt15sqrt6=sqrt(15xx6)$

Simplify.

$sqrt15sqrt6=sqrt90$

Prime factorize the radicand.

$sqrt(2xx3^2xx5)$

Apply $sqrt(a^2)=a$

$3sqrt10$