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What is the square root of 125 times the cube root of 25?

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Konstantinos Michailidis

Sep 22, 2015

It is

$sqrt125*(25)^(1/3)=5*5^(1/2)*5^(2/3)=5*5^(1/2+2/3)=5*5^(7/6)=5*5*5^(1/6)=25*5^(1/6)=25*root(6)5$

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