What is the speed of an object that travels from ( 8 , 4, 1 ) to ( 6 , -1, 6 ) over 4 s?

1 Answer
SagarStudy
Jan 21, 2016

First of all let us find find the distance between the two given points.
The distance formula for Cartesian coordinates is

d=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2
Where x_1, y_1,z_1, and x_2, y_2,z_2 are the Cartesian coordinates of two points respectively.
Let (x_1,y_1,z_1) represent (8,4,1) and (x_2,y_2,z_2) represent (6,-1,6).
implies d=sqrt((6-8)^2+(-1-4)^2+(6-1)^2
implies d=sqrt((-2)^2+(-5)^2+(5)^2
implies d=sqrt(4+25+25
implies d=sqrt(54 units

Hence the distance is sqrt54 units.

Speed=(Distance)/(Time)

Speed=sqrt54/4=1.837(units)/sec

If the units is meter then
Speed=1.837m/s.

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