What is the speed of an object that travels from ( 6, -3, 1) to (-1, -2, 7 ) over 4 s?

1 Answer
Jun 5, 2017

The speed is =2.32ms^-1

Explanation:

The distance between the points A=(x_A,y_A,z_A) and the point B=(x_B,y_B,z_B) is

AB=sqrt((x_B-x_A)^2+(y_B-y_A)^2+(z_B-z_A)^2)

dt= sqrt((-1-6)^2+(-2+3)^2+(7-1)^2)

=sqrt(7^2+1^2+6^2)

=sqrt(49+1+36)

=sqrt86

=9.27m

The speed is

v=d/t=9.27/4=2.32ms^-1