What is the speed of an object that travels from ( -5 , 2, -8) to (6 , -2, 7 ) over 4 s?

1 Answer
ali ergin
Feb 22, 2016

v~=4,76m/s

Explanation:

P_1=(x_1,y_1,z_1)
P_2=(x_2,y_2,z_2)
Delta x=x_2-x_1
Delta y=y_2-y_1
Delta z=z_2-z_1
"distance between two points is given by:"
Delta s=sqrt(Delta x^2+ Delta y^2+ Delta z^2)
Delta s=sqrt(11^2+(-4)^2+15^2)=sqrt(121+16+225)
Delta s=sqrt362
Delta s ~=19,03m
v=(Delta s)/(Delta t)
v=(19,03)/4
v~=4,76m/s

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