What is the speed of an object that travels from ( -4,6,1) to ( 9,3,7 ) over 2 s?

1 Answer
Jun 21, 2018

The speed is =7.31ms^-1

Explanation:

The speed is

v=d/t

The distance is

d=sqrt((9-(-4))^2+(3-6)^2+(7-1)^2)

=sqrt(13^2+3^2+6^2)

=sqrt(214)

=14.63m

The speed is

v=14.63/2=7.31ms^-1