What is the speed of an object that travels from $(- 2, - 5, 1)$ $( -2, -5, 1 )$ to $(- 5, - 7, 4)$ $( -5 , -7, 4 )$ over $2 s$ $2 s$ ?

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What is the speed of an object that travels from $(- 2, - 5, 1)$ $( -2, -5, 1 )$ to $(- 5, - 7, 4)$ $( -5 , -7, 4 )$ over $2 s$ $2 s$ ?

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Answer 1 · 2016-01-15T06:32:20

$\approx 2.345 \frac{u n i t s}{s}$ $approx 2.345 (units) /s$

Explanation:

In a Cartesian coordinate system distance d between two points $P_{1} (x_{1}, y_{1}, z_{1})$ $P_1(x_1, y_1, z_1)$ and $P_{2} (x_{2}, y_{2}, z_{2})$ $P_2(x_2, y_2, z_2)$ is given by the formula

$d = \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2} + {(z_{2} - z_{1})}_{2}^{2}}$ $d=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

Inserting given values $(- 2, - 5, 1)$ $(−2,−5,1)$ and $(- 5, - 7, 4)$ $(−5,−7,4)$ for the points $P_{1}$ $P_1$ and $P_{2}$ $P_2$

$d = \sqrt{{(- 5 - (- 2))}^{2} + {(- 7 - (- 5))}^{2} + {(4 - 1)}^{2}}$ $d=sqrt((-5-(-2))^2+(-7-(-5))^2+(4-1)^2)$
$d = \sqrt{22}$ $d=sqrt 22$
Now using the formula $s p e e d = \frac{d i s t a n c e}{t i m e}$ $speed = (dist ance)/(time)$
$d = \frac{\sqrt{22}}{2}$ $d=sqrt 22/2$

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What is the speed of an object that travels from $(- 2, - 5, 1)$ $( -2, -5, 1 )$ to $(- 5, - 7, 4)$ $( -5 , -7, 4 )$ over $2 s$ $2 s$ ?

1 Answer

Explanation:

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What is the speed of an object that travels from (−2,−5,1)( -2, -5, 1 ) to (−5,−7,4)( -5 , -7, 4 ) over 2s2 s?

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What is the speed of an object that travels from $(- 2, - 5, 1)$ $( -2, -5, 1 )$ to $(- 5, - 7, 4)$ $( -5 , -7, 4 )$ over $2 s$ $2 s$ ?