What is the speed of an object that travels from ( -2,1,2) to ( -3, 0,-6 ) over 3 s?

1 Answer
Dec 29, 2015

1.41"units""/s"

Explanation:

To get the distance between 2 points in 3D space you effectively use Pythagoras in 2 D (x.y) and then apply that result to 3D (x,y,z).

Lets call P=(-2,1,2)

and Q=(-3,0,6)

Then d(P,Q)=stackrel(rarr)(PQ)

=sqrt((-2+3)^2+(1-0)^2+(2-6)^2)

=sqrt(18)

=4.24

:.v=4.24/3=1.41"units/s"