What is the slope of the line that contains the points (-6, -2) and (3, -2)?
1 Answer
Oct 27, 2016
slope = 0
Explanation:
To find the slope use the
#color(blue)"gradient formula"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#
where m represents the slope and# (x_1,y_1),(x_2,y_2)" are 2 points on the line"# The 2 points here are (-6 ,-2) and (3 ,-2)
let
# (x_1,y_1)=(-6,-2)" and " (x_2,y_2)=(3,-2)#
#rArrm=(-2-(-2))/(3-(-6))=0/9=0# However, if we consider the 2 points (-6 ,-2) and (3 ,-2) we note that the y-coordinates have the same value. That is y = -2
This indicates that the line is horizontal and parallel to the x-axis.
Since the x-axis has a slope = 0, then the slope of a parallel line to it will also have a slope = 0.
