What is the slope of the line passing through the following points: # (2,-6) ; (-6,-1)#?

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Answer 1 · 2018-06-22T16:01:40

#-5/4#

#m=(y_2-y_1)/(x_2-x_1)=(-1-(-6))/(-6-(-2))=-5/4#

Answer 2 · 2018-08-10T02:33:30

The slope is #-5/8#.

Use the slope equation:

#m=(y_2-y_1)/(x_2-x_1)#,

where:

#m# is the slope, #(x_1,y_1)# is one point, and #(x_2,y_2)# is the other point.

I'm going to make #(2,-6)# the first point, and #(-6,-1)# the second point. You can do the opposite and you will get the same slope.

#m=(-1-(-6))/(-6-2)#

#m=(-1+6)/(-8)#

#m=5/(-8)#

#m=-5/8#