What is the slope of #f(x)=-xe^x-x^2# at #x=1#? Calculus Derivatives Slope of a Curve at a Point 1 Answer A. S. Adikesavan Mar 2, 2016 #-#2 ( 1 + e ), e = 2.718281828.... Explanation: #d/dx#f(x) = #-#e^x #-#xe^x #-#2x Answer link Related questions How do I find the slope of a curve at a point? How do you find the slope of a curve at a point? Slope of a curve #y=x^2-3# at the point where #x=1#? How do you use the derivative to find the slope of a curve at a point? How do you find the slope of a demand curve? What is the slope of the tangent line at a minimum of a smooth curve? How do you find the Slope of the curve #y=sqrt(x)# at the point where #x=4#? How do you find the slope of the tangent line using the formal definition of a limit? How do you find the slope of the tangent line to the graph of #f(x)=-x^2+4sqrt(x)# at x = 4? What is the slope of the line tangent to the graph of the function #f(x)=ln(sin^2(x+3))# at the... See all questions in Slope of a Curve at a Point Impact of this question 1471 views around the world You can reuse this answer Creative Commons License