What is the slope of #f(x)=-e^x # at #x=-2#? Calculus Derivatives Slope of a Curve at a Point 1 Answer Leland Adriano Alejandro Jan 10, 2016 #SLOPE = -1/e^2# Explanation: #f(x) = -e^x# #f' (x)=(-1)e^x# #f' (-2)=-1e^-2# #f' (-2)= -1/e^2# Answer link Related questions How do I find the slope of a curve at a point? How do you find the slope of a curve at a point? Slope of a curve #y=x^2-3# at the point where #x=1#? How do you use the derivative to find the slope of a curve at a point? How do you find the slope of a demand curve? What is the slope of the tangent line at a minimum of a smooth curve? How do you find the Slope of the curve #y=sqrt(x)# at the point where #x=4#? How do you find the slope of the tangent line using the formal definition of a limit? How do you find the slope of the tangent line to the graph of #f(x)=-x^2+4sqrt(x)# at x = 4? What is the slope of the line tangent to the graph of the function #f(x)=ln(sin^2(x+3))# at the... See all questions in Slope of a Curve at a Point Impact of this question 1999 views around the world You can reuse this answer Creative Commons License