What is the slope and of the line that passes (-2, -4) and (-7, -4)?

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What is the slope and of the line that passes (-2, -4) and (-7, -4)?

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Answer 1 · 2017-09-20T01:10:58

$0$ $0$

Explanation:

To get the slope, it might be easier for you to make a table:

$x : - 2, - 7$ $x:" " -2 , -7$

$y : - 4, - 4$ $y:" " -4 , -4$

A slope is the change in $y$ $y$ over the change in $x$ $x$ . To get the change, you subtract, $- 4$ $-4$ minus $- 4$ $-4$ is $0$ $0$ . $- 2$ $-2$ minus $- 7$ $-7$ is $5$ $5$ .

$\frac{- 4 - (- 4)}{- 2 - (- 7)} = \frac{0}{5} = 0$ $(-4 - (-4))/(-2 - (-7)) = 0/5 = 0$

This line has no slope. It is a straight line parallel to the x-axis.

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What is the slope and of the line that passes (-2, -4) and (-7, -4)?

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