What is the range of the function $y=8x-3$ ?

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Answer 1 · 2017-11-29T01:39:12

Range of $y$ is $(-oo,+oo)$

$y=8x-3$

First note that $y$ is a straight line with slope of $8$ and $y-$ intercept of $-3$

The range of a function is the set of all valid outputs (" $y-$ values") over its domain.

The domain of all straight lines (other than the vertical ones) is $(-oo,+oo)$ since they are defined for all values of $x$

Hence, the domain of $y$ is $(-oo,+oo)$

Also, since $y$ has no upper or lower bounds, the range of $y$ is also $(-oo,+oo)$

Answer 2 · 2017-11-29T01:45:13

$-oo<=y<=oo$ (all real numbers ( $R$ ))

Just remember that the range for a linear function is always all real numbers unless it is horizontal (doesn't have $x$ ).

One example of a linear function with a range of not all real numbers would be $f(x)=3$ . The range for this function would be $y=3$ .

I hope that helps!

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