What is the range of the function $y^2=x+1$ ?

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Answer 1 · 2017-11-11T13:57:24

It is $y >= 0$ .

$y = sqrt(x + 1)$

There can be no negative number in square roots; therefore the lowest number which $x$ can be is -1.

What is the range of the function y^2=x+1y^2=x+1?