What is the range of the function (x-1)/(x-4)?

2 Answers
Jun 2, 2017

The range of (x-1)/(x-4) is RR"\"{1} a.k.a. (-oo, 1) uu (1, oo)

Explanation:

Let:

y = (x-1)/(x-4) = (x-4+3)/(x-4) = 1+3/(x-4)

Then:

y - 1 = 3/(x-4)

Hence:

x-4 = 3/(y-1)

Adding 4 to both sides, we get:

x = 4+3/(y-1)

All these steps are reversible, except division by (y-1), which is reversible unless y=1.

So given any value of y apart from 1, there is a value of x such that:

y = (x-1)/(x-4)

That is, the range of (x-1)/(x-4) is RR"\"{1} a.k.a. (-oo, 1) uu (1, oo)

Here's the graph of our function with its horizontal asymptote y=1

graph{(y-(x-1)/(x-4))(y-1) = 0 [-5.67, 14.33, -4.64, 5.36]}

If the graphing tool allowed, I would also plot the vertical asymptote x=4

Jun 2, 2017

y inRR,y!=1

Explanation:

"rearrange "y=(x-1)/(x-4)" making x the subject"

rArry(x-4)=x-1larrcolor(blue)" cross-multiplying"

rArrxy-4y=x-1

rArrxy-x=-1+4y

rArrx(y-1)=4y-1

rArrx=(4y-1)/(y-1)

"the denominator of x cannot be zero as this would make"
"x undefined."

"equating the denominator to zero and solving gives the"
"value that y cannot be"

"solve " y-1=0rArry=1larrcolor(red)" excluded value"

rArr"range is " y inRR,y!=1