What is the range of the function $\sqrt{2 x - 8}$ $sqrt(2x-8)$ ?

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What is the range of the function $\sqrt{2 x - 8}$ $sqrt(2x-8)$ ?

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Answer 1 · 2017-05-01T12:02:03

Range $\geq 0$ $>=0$

Explanation:

There are two rules about square roots:
(1)
The argument must be non-negative, or $2 x - 8 \geq 0$ $2x-8>=0$
This means the domain is restricted to $x \geq 4$ $x>=4$
(2)
The function has a non-negative outxome. Since everything down to $0$ $0$ is possible (when $x = 4$ $x=4$ ) the range is $\geq 0$ $>=0$

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What is the range of the function $\sqrt{2 x - 8}$ $sqrt(2x-8)$ ?

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What is the range of the function $\sqrt{2 x - 8}$ $sqrt(2x-8)$ ?