What is the range of the function # h(x) = 1 /(x^2 - 9)#?

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What is the range of the function # h(x) = 1 /(x^2 - 9)#?

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Answer 1 · 2017-04-17T07:33:07

#y\geq -1/9#, #yne 0#

Explanation:

#y# is in the range if and only if the polynomial #p(x)=yx^2-y9-1=0# has a root, and it has a root if and only if #9+1/ygeq 0# and #yne 0#, so
#y\geq -1/9#, #yne 0#

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What is the range of the function # h(x) = 1 /(x^2 - 9)#?

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