What is the range of f(x) = 2x^2 + 1?

1 Answer
Jim G.
Jul 29, 2018

y in[1,oo)

Explanation:

"We require the vertex and whether it is a max/min"
"turning point"

y=2x^2+1

"is symmetrical about the y-axis and the coordinates of"
"it's vertex are"

"vertex "=(0,1)

"since "a>0" then it has a minimum turning point "uuu

"range is "y in[1,oo)
graph{2x^2+1 [-10, 10, -5, 5]}

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