What is the radius of convergence of sum_1^oo (x-1)^n / 2^(2n)?? Calculus Power Series Determining the Radius and Interval of Convergence for a Power Series 1 Answer Cesareo R. Jul 9, 2016 3 < x < 5 Explanation: sum_1^oo (x-1)^n / 2^(2n)=sum_1^oo ((x-1)/4)^n Making y = (x-1)/4 sum_1^oo (x-1)^n / 2^(2n) equiv sum_1^oo y^n We know that for abs y < 1 sum_1^oo y^n = 1/(1-y) or equivalently sum_1^oo (x-1)^n / 2^(2n)=4/(5-x) for abs((x-1)/4)<1 or 3 < x < 5 Answer link Related questions How do you find the radius of convergence of a power series? How do you find the radius of convergence of the binomial power series? What is the radius of convergence for a power series? What is interval of convergence for a Power Series? How do you find the interval of convergence for a power series? How do you find the radius of convergence of sum_(n=0)^oox^n ? What is the radius of convergence of the series sum_(n=0)^oo(x-4)^(2n)/3^n? How do you find the interval of convergence for a geometric series? What is the interval of convergence of the series sum_(n=0)^oo((-3)^n*x^n)/sqrt(n+1)? What is the radius of convergence of the series sum_(n=0)^oo(n*(x+2)^n)/3^(n+1)? See all questions in Determining the Radius and Interval of Convergence for a Power Series Impact of this question 1712 views around the world You can reuse this answer Creative Commons License