What is the radius of convergence of sum_1^oo e^(nx) / 2^(2n)?? Calculus Power Series Determining the Radius and Interval of Convergence for a Power Series 1 Answer Cesareo R. Jul 18, 2016 x < log_e 4 Explanation: S(x)=sum_1^oo e^(nx) / 2^(2n)=sum_1^oo(e^x/4)^n this series converges for e^x/4 <1 giving as result S(x) = 1/(1-e^x/4) = 4/(4-e^x), forall x | e^x<4->x < log_e 4 Answer link Related questions How do you find the radius of convergence of a power series? How do you find the radius of convergence of the binomial power series? What is the radius of convergence for a power series? What is interval of convergence for a Power Series? How do you find the interval of convergence for a power series? How do you find the radius of convergence of sum_(n=0)^oox^n ? What is the radius of convergence of the series sum_(n=0)^oo(x-4)^(2n)/3^n? How do you find the interval of convergence for a geometric series? What is the interval of convergence of the series sum_(n=0)^oo((-3)^n*x^n)/sqrt(n+1)? What is the radius of convergence of the series sum_(n=0)^oo(n*(x+2)^n)/3^(n+1)? See all questions in Determining the Radius and Interval of Convergence for a Power Series Impact of this question 2352 views around the world You can reuse this answer Creative Commons License