What is the quadratic regression equation for the data set?

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1 Answer
Feb 1, 2018

y=0.056x^2+1.278x-0.886

Explanation:

"substitute the given values for x into the equations and"
"check result against the corresponding value of y"

"the 'simplest ' value to start with is x = 10"

" starting with the first equation and working down"

"looking for an answer of "x=10toy=17.48

y=0.056x^2+1.278xto(color(red)(1))

color(white)(y)=(0.056xx100)+(1.278xx10)

color(white)(y)=5.6+12.78=18.38!=17.48

y=0.056x^2-1.278x-0.886to(color(red)(2))

color(white)(y)=(0.056xx100)-(1.278xx10)-0.886

color(white)(y)=5.6-12.78-0.886=-8.066!=17.48

y=0.056x^2+1.278to(color(red)(3))

color(white)(y)=(0.056xx100)+1.278

color(white)(y)=5.6+1.278=6.878!=17.48

y=0.056x^2+1.278x-0.886to(color(red)(4))

color(white)(y)=(0.056xx100)+(1.278xx10)-0.886

color(white)(y)=5.6+12.78-0.886=17.49~~17.48color(white)(x)✔︎

"this appears to be the correct equation"

"As a further test choose some other values of x "